Lattice spacing
Claim
Adjacent lattice points sit exactly r√2 apart.
Construction
Take the grid of tangent circles and turn it 45°. Circle centres and diamond centres now alternate along both the horizontal and the vertical. Call the common spacing s.
Each lattice point is either a circle centre or a diamond centre, and a tile occupies one of each, adjacent.
Proof
In the unturned picture, four circle centres form a square of side 2r with the diamond at its centre. The distance from a corner to the centre of a square of side 2r is half the diagonal: (2r√2)/2 = r√2.
s = r√2 ≈ 1.41421r
Note that s is larger than r but smaller than 2r. The tile is 2r wide on a lattice of pitch 1.414r, which is exactly why neighbouring tiles interlock rather than sitting side by side: each one overhangs its own cell.
Note
Aaron's slot.
Open questions
- The project writes this step as both s and S. One letter would do.
Checks
| What | How | Source |
|---|---|---|
| Junction spacing on the tile | All six junction chords measure 141.422 at r = 100, against r√2 = 141.4214 | _src/core.py |
| Same-type pitch | Two circle centres of the same parity are 2s = 2.828r apart, measurable on any board | reference/geometry-constants.md |
| Lattice formula on file | P(a,b) = a·U + b·V with U = (r√2, r√2), V = (−r√2, r√2) | nuna_master_reference.md |