The diamond’s area
Claim
The void between four tangent circles has area (4 − π)r2.
Construction
Four circles of radius r sit with their centres on the corners of a square of side 2r, so adjacent circles are tangent. At the middle of that square is a region touched by none of them, bounded by four concave arcs of radius r. That is the diamond.
Proof
Take the square whose corners are the four centres: side 2r, area 4r2. Each circle contributes exactly one quarter-disc to the interior of that square, because the corner angle is 90°, and four quarter-discs make one whole disc, πr2.
4r2 − πr2 = (4 − π)r2 ≈ 0.8584r2
Each corner offcut from Claim A is a quarter of this, (4 − π)r2/4 ≈ 0.2146r2, which is the smallest natural unit in the whole system.
Note
Aaron's slot.
Open questions
- Whether the offcut deserves a name of its own in the project's vocabulary. It is the unit everything else is measured in, and it is currently called the offcut only here.
Checks
| What | How | Source |
|---|---|---|
| Two routes, one number | Square minus circle here; four offcuts assembled in Claim A | reference/geometry-constants.md |
| Arithmetic | (4 − π) = 0.858407 and a quarter of it is 0.214602 | reference/geometry-constants.md |